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(D) To determine the magnetic moment,we calculate the number of unpaired electrons $(n)$ in each complex:$I.$ $[Mn(CN)_6]^{3-}$: $Mn^{3+}$ is $3d^4$.

Vedclass · Accepted Answer

$III < I < II < IV$

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(D) To determine the magnetic moment,we calculate the number of unpaired electrons $(n)$ in each complex:$I.$ $[Mn(CN)_6]^{3-}$: $Mn^{3+}$ is $3d^4$. $CN^-$ is a strong field ligand,causing pairing. $n = 2$. Magnetic moment $\mu = \sqrt{2(2+2)} = \sqrt{8} \approx 2.83 \ BM$.$II.$ $[MnCl_6]^{3-}$: $Mn^{3+}$ is $3d^4$. $Cl^-$ is a weak field ligand,no pairing. $n = 4$. Magnetic moment $\mu = \sqrt{4(4+2)} = \sqrt{24} \approx 4.90 \ BM$.$III.$ $[Fe(CN)_6]^{3-}$: $Fe^{3+}$ is $3d^5$. $CN^-$ is a strong field ligand,causing pairing. $n = 1$. Magnetic moment $\mu = \sqrt{1(1+2)} = \sqrt{3} \approx 1.73 \ BM$.$IV.$ $[FeF_6]^{3-}$: $Fe^{3+}$ is $3d^5$. $F^-$ is a weak field ligand,no pairing. $n = 5$. Magnetic moment $\mu = \sqrt{5(5+2)} = \sqrt{35} \approx 5.92 \ BM$.Comparing the values: $1.73 (III) Thus,the increasing order is $III < I < II < IV$.

Arrange the following in the increasing order of their magnetic moments:
$I.$ $[Mn(CN)_6]^{3-}$
$II.$ $[MnCl_6]^{3-}$
$III.$ $[Fe(CN)_6]^{3-}$
$IV.$ $[FeF_6]^{3-}$

Similar Questions

Given below are two statements:
Statement $I$: $A$ solution of $[Ni(H_2O)_6]^{2+}$ is green in colour.
Statement $II$: $A$ solution of $[Ni(CN)_4]^{2-}$ is colourless.
In the light of the above statements,choose the most appropriate answer from the options given below:

The pair having the same magnetic moment is $:$
[At. No.$: $ $Cr= 24, Mn= 25, Fe= 26, Co= 27$]

Identify the number of complexes that are optically active:
$[Co(en)_3]^{3+}$; $[Co(NH_3)_4Cl_2]^{+}$; $[CoCl_2(en)_2]^{+}$; $[Co(NH_3)_3(NO_2)_3]$

$STATEMENT-1$: The geometrical isomers of the complex $[M(NH_3)_4Cl_2]$ are optically inactive.
$STATEMENT-2$: Both geometrical isomers of the complex $[M(NH_3)_4Cl_2]$ possess a plane of symmetry.

Which from the following ligands is able to form linkage isomers?

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Arrange the following in the increasing order of their magnetic moments:$I.$ $[Mn(CN)_6]^{3-}$$II.$ $[MnCl_6]^{3-}$$III.$ $[Fe(CN)_6]^{3-}$$IV.$ $[FeF_6]^{3-}$