Arrange the following ions in the correct ord | vedclass

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(A) The electronic configuration of $Be^{2+}$ is $[He]$,$Na^{+}$ is $[Ne]$,$Cl^{-}$ is $[Ar]$ and $Br^{-}$ is $[Kr]$.As we move down the group,the num

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$Br^{-} > Cl^{-} > Na^{+} > Be^{2+}$

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(A) The electronic configuration of $Be^{2+}$ is $[He]$,$Na^{+}$ is $[Ne]$,$Cl^{-}$ is $[Ar]$ and $Br^{-}$ is $[Kr]$.As we move down the group,the number of shells increases,leading to an increase in ionic radius.Since $Be^{2+}$ has $2$ shells,$Na^{+}$ has $3$ shells,$Cl^{-}$ has $4$ shells,and $Br^{-}$ has $5$ shells,the order of ionic radii is $Br^{-} > Cl^{-} > Na^{+} > Be^{2+}$.

Arrange the following ions in the correct order with respect to their ionic radii.

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