Arrange the following materials in increasing | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The resistivity $(ho)$ of materials at room temperature is as follows:$1$. Copper $(Cu)$ (Conductor): $\approx 1.7 	imes 10^{-8} \ \Omega \cdot

Vedclass · Accepted Answer

Copper $ < $ Nichrome $ < $ Germanium $ < $ Silicon

Vedclass · Answer

(A) The resistivity $(ho)$ of materials at room temperature is as follows:$1$. Copper $(Cu)$ (Conductor): $\approx 1.7 	imes 10^{-8} \ \Omega \cdot m$$2$. Nichrome (Alloy): $\approx 1.0 	imes 10^{-6} \ \Omega \cdot m$ (or $100 	imes 10^{-8} \ \Omega \cdot m$)$3$. Germanium (Semiconductor): $\approx 0.46 \ \Omega \cdot m$$4$. Silicon (Semiconductor): $\approx 2300 \ \Omega \cdot m$Comparing these values,the increasing order of resistivity is: Copper Therefore,the correct option is $A$.

Arrange the following materials in increasing order of their resistivity: Nichrome,Copper,Germanium,Silicon.

Similar Questions

$A$ wire of circular cross-section has an inner portion of radius $R$ made of a material of resistivity $\rho$ and is surrounded by an outer portion of thickness $R$ made of a material of double resistivity. Find the resistance of a length $l$ of such a wire.

Two metal wires of identical dimensions are connected in series. If $\sigma_1$ and $\sigma_2$ are the conductivities of the metal wires respectively,the effective conductivity of the combination is

$A$ wire of resistance $5 \Omega$ is stretched so that its new length is $3$ times its original length. What is the resistance of the new wire?

The current flowing through a conductor connected across a source is $2\,A$ and $1.2\,A$ at $0^{\circ}C$ and $100^{\circ}C$ respectively. The current flowing through the conductor at $50^{\circ}C$ will be $......\times 10^2\,mA$.

What is the resistivity of a perfect conductor?

Vedclass Test Series

Exam Paper Generator

Online Exam Module