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(A) The strength of intermolecular forces in polymers follows the order: Fibres > Thermoplastics > Elastomers.$1$. $Nylon-6$ $(A)$ is a fibre,which co

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$A > C > B$

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(A) The strength of intermolecular forces in polymers follows the order: Fibres > Thermoplastics > Elastomers.$1$. $Nylon-6$ $(A)$ is a fibre,which contains strong hydrogen bonding between the polymer chains,resulting in the strongest intermolecular forces.$2$. $Polyvinyl$ $chloride$ $(C)$ is a thermoplastic,which has dipole-dipole interactions that are stronger than the weak van der Waals forces found in elastomers but weaker than hydrogen bonds.$3$. $Neoprene$ $(B)$ is an elastomer,which has weak van der Waals forces between the polymer chains,making it the weakest among the three.Therefore,the correct order of strength is $A > C > B$.

List-$I$	List-$II$
$A$. $Nylon$ $6,6$	$i$. $Ethylene$ $glycol$ and $Terephthalic$ $acid$
$B$. $Terylene$	$ii$. $1,3-Butadiene$ and $Styrene$
$C$. $Buna-S$	$iii$. $Chloroprene$
$D$. $Neoprene$	$iv$. $Acrylonitrile$
	$v$. $Adipic$ $acid$ and $Hexamethylenediamine$

List-$I$	List-$II$
$A$. Natural rubber	$i$. $\beta$-glucose
$B$. Cellulose	$ii$. Isoprene
$C$. Nylon-$6$	$iii$. Tetrafluoroethylene
$D$. Teflon	$iv$. Caprolactam

Arrange the following polymers in order of increasing strength of their intermolecular forces:
$Nylon-6$ $(A)$,$Neoprene$ $(B)$,$Polyvinyl$ $chloride$ $(C)$

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Match the following items in List-$I$ with their corresponding monomer units in List-$II$.
List-$I$ List-$II$
$A$. Natural rubber $i$. $\beta$-glucose
$B$. Cellulose $ii$. Isoprene
$C$. Nylon-$6$ $iii$. Tetrafluoroethylene
$D$. Teflon $iv$. Caprolactam

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Arrange the following polymers in order of increasing strength of their intermolecular forces:$Nylon-6$ $(A)$,$Neoprene$ $(B)$,$Polyvinyl$ $chloride$ $(C)$