Arrange the following compounds in decreasing | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Basic strength is directly proportional to the electron-donating groups ($+M, +H, +I$ effects) and inversely proportional to electron-withdrawing

Vedclass · Accepted Answer

$(iv) > (i) > (iii) > (ii)$

Vedclass · Answer

(C) Basic strength is directly proportional to the electron-donating groups ($+M, +H, +I$ effects) and inversely proportional to electron-withdrawing groups ($-M, -H, -I$ effects).$(i)$ Aniline: Reference compound.(ii) $p$-Nitroaniline: $-NO_2$ group has strong $-M$ and $-I$ effects,which significantly decrease basic strength.(iii) $p$-Cyanoaniline: $-CN$ group has $-M$ and $-I$ effects,which decrease basic strength,but less than $-NO_2$.(iv) $p$-Toluidine: $-CH_3$ group has $+H$ and $+I$ effects,which increase basic strength.Comparing the effects: The order of electron-withdrawing power is $-NO_2 > -CN$. Thus,the order of basic strength is $(iv) > (i) > (iii) > (ii)$.

Arrange the following compounds in decreasing order of basic strength:
$(i)$ Aniline
(ii) $p$-Nitroaniline
(iii) $p$-Cyanoaniline
(iv) $p$-Toluidine

Similar Questions

Identify the $X$ in the reaction.
$R-NH_2 + HNO_2 \underset{273-278 \ K}{}$ ${\xrightarrow{NaNO_2 + HCl}} X$ $\xrightarrow{H_2O} R-OH + N_2 + HCl$

Amines behave as

In the given pair of compounds,in which pair does the second compound have a higher boiling point than the first compound?

The preferred sites of protonation in the following compounds are:
$(i)$ $CH_3CONHCH_3$
(ii) $2$-aminopyridine

Explain why $MeNH_2$ is a stronger base than $MeOH$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Arrange the following compounds in decreasing order of basic strength:$(i)$ Aniline(ii) $p$-Nitroaniline(iii) $p$-Cyanoaniline(iv) $p$-Toluidine