Arun gives his wife Asha a birthday gift,givi | vedclass

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(A) The number of days between $January \, 1$ and $August \, 8$ (assuming a non-leap year) is calculated as: $31 (Jan) + 28 (Feb) + 31 (Mar) + 30 (Apr

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$1000$

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(A) The number of days between $January \, 1$ and $August \, 8$ (assuming a non-leap year) is calculated as: $31 (Jan) + 28 (Feb) + 31 (Mar) + 30 (Apr) + 31 (May) + 30 (Jun) + 31 (Jul) + 8 (Aug) = 219 	ext{ days}$.This duration represents $\frac{219}{365} = \frac{3}{5}$ of a year.Arun needs to provide $Rs. \, 42$ as a gift when she turns $42$. He invests a principal $P$ at a simple interest rate of $7 \%$ per annum for $\frac{3}{5}$ of a year to accumulate this amount.Using the simple interest formula $SI = \frac{P 	imes R 	imes T}{100}$:$42 = \frac{P 	imes 7 	imes 3}{100 	imes 5}$$42 = \frac{21 	imes P}{500}$$P = \frac{42 	imes 500}{21} = 2 	imes 500 = 1000$.Therefore,the required sum is $Rs. \, 1000$.

Arun gives his wife Asha a birthday gift,giving her each year a number of rupees equal to the number of years of her age. If her birthday falls on $August \, 8$,what sum must be placed at simple interest at $7 \%$ on $January \, 1$,before she is $42$,in order to raise the required sum (in $Rs.$)?

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