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(D) In ${C_3}$ plants,the synthesis of one molecule of glucose $(C_6H_{12}O_6)$ requires $18$ $ATP$ and $12$ $NADPH$ molecules.In ${C_4}$ plants,an ad

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(D) In ${C_3}$ plants,the synthesis of one molecule of glucose $(C_6H_{12}O_6)$ requires $18$ $ATP$ and $12$ $NADPH$ molecules.In ${C_4}$ plants,an additional $C_4$ cycle (Hatch-Slack pathway) operates to concentrate $CO_2$ around the enzyme $RuBisCO$.This process requires $2$ additional $ATP$ molecules per $CO_2$ molecule fixed to regenerate phosphoenolpyruvate $(PEP)$.Since $6$ molecules of $CO_2$ are required to produce one molecule of hexose sugar,the total additional $ATP$ required is $6 	imes 2 = 12$ $ATP$ molecules.Therefore,${C_4}$ plants require a total of $30$ $ATP$ $(18 + 12)$ to produce one molecule of glucose.

As compared to a ${C_3}$ plant,how many additional molecules of $ATP$ are needed for the net production of one molecule of hexose sugar by ${C_4}$ plants?

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