As shown in the adjoining diagram of a stairc | vedclass

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(B) From the diagram,there are $4$ steps in total.Total horizontal distance (base) $= 4 	imes 20 \, cm = 80 \, cm = 0.8 \, m$.Total vertical distance

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(B) From the diagram,there are $4$ steps in total.Total horizontal distance (base) $= 4 	imes 20 \, cm = 80 \, cm = 0.8 \, m$.Total vertical distance (height) $= 4 	imes 15 \, cm = 60 \, cm = 0.6 \, m$.The distance between points $A$ and $B$ forms the hypotenuse of a right-angled triangle with base $0.8 \, m$ and height $0.6 \, m$.Using the Pythagorean theorem: $AB = \sqrt{(0.8)^2 + (0.6)^2} = \sqrt{0.64 + 0.36} = \sqrt{1.00} = 1 \, m$.

As shown in the adjoining diagram of a staircase,the width of each step is $20 \, cm$ and the height is $15 \, cm$. Find the distance between points $A$ and $B$ in meters.

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