As shown in the diagram,the side length of sq | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The side length of the square $ABCD$ is $s = 35 \, cm$.The area of the square $ABCD = s^2 = 35^2 = 1225 \, cm^2$.There are two semicircles drawn o

Vedclass · Accepted Answer

$262.5$

Vedclass · Answer

(D) The side length of the square $ABCD$ is $s = 35 \, cm$.The area of the square $ABCD = s^2 = 35^2 = 1225 \, cm^2$.There are two semicircles drawn on sides $\overline{AB}$ and $\overline{CD}$ with diameter $d = 35 \, cm$,so the radius $r = \frac{35}{2} = 17.5 \, cm$.The area of two semicircles = $2 	imes (\frac{1}{2} \pi r^2) = \pi r^2 = \frac{22}{7} 	imes 17.5 	imes 17.5 = 22 	imes 2.5 	imes 17.5 = 962.5 \, cm^2$.The area of the shaded region = (Area of square) - (Area of two semicircles) = $1225 - 962.5 = 262.5 \, cm^2$.

As shown in the diagram,the side length of square $ABCD$ is $35 \, cm$. Two semicircles are drawn on its sides $\overline{AB}$ and $\overline{CD}$ as diameters. Find the area of the shaded region in $cm^2$.

Similar Questions

The floor of a room has dimensions $5 \, m \times 4 \, m$ and it is covered with circular tiles of diameter $50 \, cm$ each,as shown in the figure. Find the area of the floor that remains uncovered by the tiles. (Use $\pi = 3.14$) (in $m^2$)

The radius of a wheel of a car is $21 \, cm$. If it makes $800$ rotations per minute,find the speed of the car in $km/h$.

In the figure,a square is inscribed in a circle of diameter $d$ and another square is circumscribing the circle. Is the area of the outer square four times the area of the inner square? Give reasons for your answer.

Find the area of the shaded field shown in the figure.

In covering a distance $s$ metres,a circular wheel of radius $r$ metres makes $\frac{s}{2 \pi r}$ revolutions. Is this statement true? Why?

Vedclass Test Series

Exam Paper Generator

Online Exam Module