As shown in the figure,charges +q and -q are | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The electric potential $V$ at a point due to a point charge $Q$ at a distance $r$ is given by $V = \frac{1}{4\pi \epsilon_0} \cdot \frac{Q}{r}$.In

Vedclass · Accepted Answer

zero

Vedclass · Answer

(B) The electric potential $V$ at a point due to a point charge $Q$ at a distance $r$ is given by $V = \frac{1}{4\pi \epsilon_0} \cdot \frac{Q}{r}$.In the given isosceles triangle,the distance from vertex $A$ to vertex $B$ is $a$,and the distance from vertex $A$ to vertex $C$ is also $a$ (since it is an isosceles triangle with $AB = AC = a$).The potential at vertex $A$ due to charge $+q$ at $B$ is $V_B = \frac{1}{4\pi \epsilon_0} \cdot \frac{+q}{a}$.The potential at vertex $A$ due to charge $-q$ at $C$ is $V_C = \frac{1}{4\pi \epsilon_0} \cdot \frac{-q}{a}$.The total potential at vertex $A$ is the algebraic sum of the individual potentials: $V_A = V_B + V_C = \frac{1}{4\pi \epsilon_0} \cdot \frac{q}{a} + \frac{1}{4\pi \epsilon_0} \cdot \frac{-q}{a} = 0$.

As shown in the figure,charges $+q$ and $-q$ are placed at the vertices $B$ and $C$ of an isosceles triangle. The potential at the vertex $A$ is

Similar Questions

How do ortho and para hydrogen differ from each other?

If $5x - 12y + 10 = 0$ and $12y - 5x + 16 = 0$ are two tangents to a circle,then the radius of the circle is

The eccentricity of the ellipse $\frac{x^2}{16} + \frac{y^2}{9} = 1$ is

Which of the following is a favourable factor for cation formation?

Which of the following is an amphoteric oxide?

Vedclass Test Series

Exam Paper Generator

Online Exam Module