As shown in the figure below, a charge +2 tex | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The work done in moving a charge in an electrostatic field is equal to the change in the electrostatic potential energy of the system.$W = U_{f} -

Vedclass · Accepted Answer

zero

Vedclass · Answer

(C) The work done in moving a charge in an electrostatic field is equal to the change in the electrostatic potential energy of the system.$W = U_{f} - U_{i}$$U = \frac{1}{4 \pi \varepsilon_{0}} \frac{q_{1} q_{2}}{r}$Initial potential energy $U_{i}$ when the charge $+5 	ext{ C}$ is at $A(2, 0) 	ext{ m}$:$U_{i} = \frac{1}{4 \pi \varepsilon_{0}} \frac{(2)(5)}{2} = \frac{1}{4 \pi \varepsilon_{0}} (5)$Final potential energy $U_{f}$ when the charge $+5 	ext{ C}$ is at $B(0, 2) 	ext{ m}$:$U_{f} = \frac{1}{4 \pi \varepsilon_{0}} \frac{(2)(5)}{2} = \frac{1}{4 \pi \varepsilon_{0}} (5)$Since the distance $r$ from the origin $O$ to point $A$ is $2 	ext{ m}$ and from the origin $O$ to point $B$ is also $2 	ext{ m}$, the potential energy remains the same.$W = U_{f} - U_{i} = 0 	ext{ J}$.

Similar Questions

$A$ hollow conducting sphere is placed in an electric field produced by a point charge placed at $P$ as shown in the figure. Let $V_A, V_B, V_C$ be the potentials at points $A, B,$ and $C$ respectively. Then:

$A$ uniform electric field of magnitude $E = 100 \ V/m$ is directed along the line $y = x + 3$. Find the potential difference $V_A - V_B$ between points $A(3, 1)$ and $B(1, 3)$.

The figure shows lines of constant potential in a region where an electric field is present. The electric field at point $B$ is............

Which of the following statements is not true?

$A$ uniform electric field of magnitude $100 \ V/m$ in space is directed along the line $y = 3 + x$. Find the potential difference between point $A(3, 1)$ and $B(1, 3)$ in Volts.

Vedclass Test Series

Exam Paper Generator

Online Exam Module