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(A) As the $s-$character of hybridized orbitals decreases,the bond angle also decreases.In $sp^3$ hybridization: $s-$character is $25\%$,bond angle is

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Decreases

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(A) As the $s-$character of hybridized orbitals decreases,the bond angle also decreases.In $sp^3$ hybridization: $s-$character is $25\%$,bond angle is $109.5^\circ$.In $sp^2$ hybridization: $s-$character is $33.3\%$,bond angle is $120^\circ$.In $sp$ hybridization: $s-$character is $50\%$,bond angle is $180^\circ$.Therefore,as the $s-$character decreases $(50\%$ $\rightarrow 33.3\%$ $\rightarrow 25\%)$,the bond angle decreases $(180^\circ$ $\rightarrow 120^\circ$ $\rightarrow 109.5^\circ)$.

As the $s-$character of a hybridized orbital decreases,the bond angle

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