Assertion : PbCl_2 is more stable than PbCl_4 | vedclass

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Question

(A) $Pb^{2+}$ is more stable than $Pb^{4+}$ due to the inert pair effect.Because of this,$PbCl_4$ decomposes readily into $PbCl_2$ and $Cl_2$ as shown

Vedclass · Accepted Answer

If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.

Vedclass · Answer

(A) $Pb^{2+}$ is more stable than $Pb^{4+}$ due to the inert pair effect.Because of this,$PbCl_4$ decomposes readily into $PbCl_2$ and $Cl_2$ as shown in the reaction: $PbCl_4 	o PbCl_2 + Cl_2$.Since $Pb^{4+}$ has a strong tendency to get reduced to $Pb^{2+}$,$PbCl_4$ acts as a powerful oxidising agent.Therefore,both the Assertion and Reason are correct,and the Reason correctly explains the Assertion.

Assertion : $PbCl_2$ is more stable than $PbCl_4$.
Reason : $PbCl_4$ is a powerful oxidising agent.

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Assertion : $PbCl_2$ is more stable than $PbCl_4$.Reason : $PbCl_4$ is a powerful oxidising agent.