Assertion : $[FeF_6]^{3-}$ is a low spin complex.
Reason : Low spin complexes have a lesser number of unpaired electrons.
Reason : Low spin complexes have a lesser number of unpaired electrons.
- AIf both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.
- BIf both Assertion and Reason are correct but Reason is not a correct explanation of the Assertion.
- CIf the Assertion is correct but Reason is incorrect.
- DIf both the Assertion and Reason are incorrect.
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Similar Questions
Match the correct option.
$A$. $[CoF_6]^{3-}$ $M$. $sp^3d^2$,paramagnetic $B$. $[Mn(CN)_6]^{3-}$ $N$. $sp^3d^2$,diamagnetic $C$. $[Co(C_2O_4)_3]^{3-}$ $O$. $d^2sp^3$,paramagnetic $D$. $[Zn(H_2O)_6]^{2+}$ $P$. $d^2sp^3$,diamagnetic
| $A$. $[CoF_6]^{3-}$ | $M$. $sp^3d^2$,paramagnetic |
| $B$. $[Mn(CN)_6]^{3-}$ | $N$. $sp^3d^2$,diamagnetic |
| $C$. $[Co(C_2O_4)_3]^{3-}$ | $O$. $d^2sp^3$,paramagnetic |
| $D$. $[Zn(H_2O)_6]^{2+}$ | $P$. $d^2sp^3$,diamagnetic |
Medium
View SolutionWhich of the following has the maximum number of unpaired electrons?
Easy
View SolutionUsing valence bond theory,explain the following in relation to the complexes given below: $[Mn(CN)_{6}]^{3-}, [Co(NH_{3})_{6}]^{3+}, [Cr(H_{2}O)_{6}]^{3+}, [FeCl_{6}]^{4-}$
$(i)$ Type of hybridisation.
$(ii)$ Inner or outer orbital complex.
$(iii)$ Magnetic behaviour.
$(iv)$ Spin only magnetic moment value.
$(i)$ Type of hybridisation.
$(ii)$ Inner or outer orbital complex.
$(iii)$ Magnetic behaviour.
$(iv)$ Spin only magnetic moment value.
Medium
View SolutionNumber of identical $Cr-O$ bonds in dichromate ion $Cr_2O_7^{2-}$ is
Easy
View SolutionConsider the following complex: $[Co(NH_3)_5CO_3]ClO_4$. The coordination number,oxidation number,number of $d-$ electrons,and number of unpaired $d-$ electrons on the metal are respectively:
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