Assertion : Potassium ferrocyanide is diamagn | vedclass

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(C) In potassium ferrocyanide,$K_4[Fe(CN)_6]$,$Fe$ is in the $+2$ oxidation state ($Fe^{2+}$: $3d^6$). Since $CN^-$ is a strong field ligand,it causes

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If the Assertion is correct but Reason is incorrect.

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(C) In potassium ferrocyanide,$K_4[Fe(CN)_6]$,$Fe$ is in the $+2$ oxidation state ($Fe^{2+}$: $3d^6$). Since $CN^-$ is a strong field ligand,it causes pairing of electrons,resulting in $t_{2g}^6 e_g^0$ configuration with $n=0$ unpaired electrons,making it diamagnetic.In potassium ferricyanide,$K_3[Fe(CN)_6]$,$Fe$ is in the $+3$ oxidation state ($Fe^{3+}$: $3d^5$). $CN^-$ causes pairing,resulting in $t_{2g}^5 e_g^0$ configuration with $n=1$ unpaired electron,making it paramagnetic.The Assertion is correct.The Reason states that crystal field splitting in ferrocyanide is greater than in ferricyanide. This is incorrect because crystal field splitting energy $(\Delta_o)$ increases with the oxidation state of the metal ion. Since $Fe^{3+}$ has a higher oxidation state than $Fe^{2+}$,the crystal field splitting in the ferricyanide ion is greater than in the ferrocyanide ion. Thus,the Reason is incorrect.

Assertion : Potassium ferrocyanide is diamagnetic,whereas potassium ferricyanide is paramagnetic.
Reason : Crystal field splitting in ferrocyanide ion is greater than that of ferricyanide ion.

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Assertion : Potassium ferrocyanide is diamagnetic,whereas potassium ferricyanide is paramagnetic.Reason : Crystal field splitting in ferrocyanide ion is greater than that of ferricyanide ion.