Assertion: tert-Butyl methyl ether is not pre | vedclass

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(B) $Assertion$ is correct because $tert$-butyl bromide is a $3^\circ$ alkyl halide,which undergoes $E2$ elimination rather than $S_N2$ substitution w

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If both Assertion and Reason are correct but Reason is not a correct explanation of the Assertion.

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(B) $Assertion$ is correct because $tert$-butyl bromide is a $3^\circ$ alkyl halide,which undergoes $E2$ elimination rather than $S_N2$ substitution when treated with a strong base like sodium methoxide. The major product is isobutylene $(CH_3-C(CH_3)=CH_2)$.$Reason$ is also correct because sodium methoxide $(CH_3ONa)$ is indeed a strong nucleophile,but its primary role in this specific reaction with a bulky $3^\circ$ substrate is that of a strong base.However,the reason for the failure of the reaction is the steric hindrance of the $3^\circ$ alkyl halide,not just the nucleophilicity of the methoxide ion. Thus,the Reason is not the correct explanation for the Assertion.

Column-$I$: Compound / Reagent	Column-$II$: Other name / Chemical / Process
$A$. Methanol	$I$. Lucas reagent
$B$. $ZnCl_2$ / Conc. $HCl$	$II$. Baeyer's reagent
$C$. Rectified spirit	$III$. Wood spirit
$D$. Dil. $KMnO_4$	$IV$. $95 \% C_2H_5OH$
-	$V$. $75 \% C_2H_5OH$
-	$VI$. $90 \% C_3H_7OH$

Assertion: $tert$-Butyl methyl ether is not prepared by the reaction of $tert$-butyl bromide with sodium methoxide.
Reason: Sodium methoxide is a strong nucleophile.

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Assertion: $tert$-Butyl methyl ether is not prepared by the reaction of $tert$-butyl bromide with sodium methoxide.Reason: Sodium methoxide is a strong nucleophile.