(A) According to the theory of relativity,the energy of a particle is given by $E^2 = (pc)^2 + (m_0c^2)^2$.For a photon,the rest mass $m_0$ is $0$.The

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(A) According to the theory of relativity,the energy of a particle is given by $E^2 = (pc)^2 + (m_0c^2)^2$.For a photon,the rest mass $m_0$ is $0$.Therefore,$E^2 = (pc)^2$,which simplifies to $E = pc$ or $p = E/c$.This relationship is derived specifically from the particle nature of the photon,which allows it to possess momentum despite having no rest mass.Thus,the Assertion is correct,and the Reason is the correct explanation for the Assertion.

Class 12 Physics Dual Nature of Radiation and Matter Particle Nature of Light : Photon

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Assertion: The energy $(E)$ and momentum $(p)$ of a photon are related by $p = E/c$.
Reason: The photon behaves like a particle.

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A
If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.
B
If both Assertion and Reason are correct but Reason is not a correct explanation of the Assertion.
C
If the Assertion is correct but Reason is incorrect.
D
If both the Assertion and Reason are incorrect.

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Dual Nature of Radiation and Matter

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Particle Nature of Light : Photon

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If the energy of a photon corresponding to a wavelength of $6000 \mathring A$ is $3.32 \times 10^{-19} \ J$,the photon energy for a wavelength of $4000 \mathring A$ will be ............ $eV$.

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The radiant energy from the Sun incident on the Earth's surface is $2 \ cal/cm^2 \cdot min$. If the average wavelength of solar radiation is $5500 \ \mathring A$,then the number of photons incident per minute on a surface area of $1 \ cm^2$ on the Earth's surface is ............ $(h = 6.6 \times 10^{-34} \ J \cdot s, 1 \ cal = 4.2 \ J)$

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Assertion: The energy $(E)$ and momentum $(p)$ of a photon are related by $p = E/c$.Reason: The photon behaves like a particle.

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If the energy of a photon corresponding to a wavelength of $6000 \mathring A$ is $3.32 \times 10^{-19} \ J$,the photon energy for a wavelength of $4000 \mathring A$ will be ............ $eV$.

Consider a hypothetical annihilation of a stationary electron with a stationary positron. What is the wavelength of the resulting radiation? ($h =$ Planck's constant,$c =$ speed of light,$m_0 =$ rest mass)

An $AIR$ station is broadcasting waves of wavelength $300 \ m$. If the radiating power of the transmitter is $10 \ kW$,then the number of photons radiated per second is:

Monochromatic light of frequency $6 \times 10^{14} \,Hz$ is produced by a laser. The power emitted is $2 \times 10^{-3} \,W$. The energy of the photon in this light beam is . . . . . . eV.

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Assertion: The energy $(E)$ and momentum $(p)$ of a photon are related by $p = E/c$.
Reason: The photon behaves like a particle.