Assertion : The number of O atoms in 16 g of | vedclass

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(C) For $16 \ g$ of oxygen $(O_2)$: $	ext{Number of atoms} = \frac{16 \ g}{32 \ g/mol} 	imes 2 	imes N_A = N_A$.For $16 \ g$ of ozone $(O_3)$: $	e

Vedclass · Accepted Answer

Assertion is true but Reason is false.

Vedclass · Answer

(C) For $16 \ g$ of oxygen $(O_2)$: $	ext{Number of atoms} = \frac{16 \ g}{32 \ g/mol} 	imes 2 	imes N_A = N_A$.For $16 \ g$ of ozone $(O_3)$: $	ext{Number of atoms} = \frac{16 \ g}{48 \ g/mol} 	imes 3 	imes N_A = N_A$.Since both contain $N_A$ atoms,the Assertion is true.Reason states that each represents $1 \ g$ molecule of oxygen,which is false because $16 \ g$ of $O_2$ is $0.5 \ mol$ and $16 \ g$ of $O_3$ is $0.33 \ mol$.

Assertion : The number of $O$ atoms in $16 \ g$ of oxygen and $16 \ g$ of ozone is same.
Reason : Each of the species represents $1 \ g$ molecule of oxygen.

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Assertion : The number of $O$ atoms in $16 \ g$ of oxygen and $16 \ g$ of ozone is same.Reason : Each of the species represents $1 \ g$ molecule of oxygen.