Assertion : When ultraviolet light is inciden | vedclass

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Question

(C) According to Einstein's photoelectric equation,$K_{max} = eV_0 = h
u - \phi$,where $
u$ is the frequency of incident light and $\phi$ is the wor

Vedclass · Accepted Answer

If the Assertion is correct but Reason is incorrect.

Vedclass · Answer

(C) According to Einstein's photoelectric equation,$K_{max} = eV_0 = h
u - \phi$,where $
u$ is the frequency of incident light and $\phi$ is the work function of the metal.Since the frequency of $X-$ rays is significantly higher than that of ultraviolet $(U.V.)$ light,the maximum kinetic energy $(K_{max})$ and the stopping potential $(V_0)$ will both increase when $X-$ rays are used.Therefore,the Assertion is correct.The Reason states that photoelectrons are emitted with a range of speeds due to a range of frequencies in the incident light. This is incorrect because photoelectric emission occurs even with monochromatic light (a single frequency),and the range of speeds arises due to energy losses of electrons within the metal before emission,not because of a range of incident frequencies.Thus,the Assertion is correct but the Reason is incorrect.

Similar Questions

In an experiment on the photoelectric effect,the frequency $\nu$ of the incident light is plotted against the stopping potential $V_0$. The work function of the photoelectric surface is given by ($e$ is the electronic charge):

In the graph given below,if the slope is $4.12 \times 10^{-15} \, V-s$,then the value of $'h'$ should be:

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