Assertion (A): Two condensers of same capacit | vedclass

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(B) Given,two capacitors of same capacity $C$.In series,the equivalent capacitance $C_S$ is given by:$\frac{1}{C_S} = \frac{1}{C} + \frac{1}{C} = \fra

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Both $A$ and $R$ are true but $R$ is not a correct explanation for $A$.

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(B) Given,two capacitors of same capacity $C$.In series,the equivalent capacitance $C_S$ is given by:$\frac{1}{C_S} = \frac{1}{C} + \frac{1}{C} = \frac{2}{C} \implies C_S = \frac{C}{2}$In parallel,the equivalent capacitance $C_P$ is given by:$C_P = C + C = 2C$The ratio of resultant capacities is:$\frac{C_P}{C_S} = \frac{2C}{C/2} = \frac{4}{1} = 4:1$Thus,Assertion $(A)$ is true.In parallel,$C_P = 2C > C$,so capacity increases.In series,$C_S = C/2 Thus,Reason $(R)$ is also true,but it describes the general behavior of capacitors in combinations rather than providing the specific mathematical derivation for the ratio $4:1$. Therefore,$R$ is not the correct explanation for $A$.

Assertion $(A)$: Two condensers of same capacity are connected first in parallel and then in series. The ratio of resultant capacities in the two cases will be $4: 1$.
Reason $(R)$: In parallel,capacity increases and in series,capacity decreases.

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Assertion $(A)$: Two condensers of same capacity are connected first in parallel and then in series. The ratio of resultant capacities in the two cases will be $4: 1$.Reason $(R)$: In parallel,capacity increases and in series,capacity decreases.