Assertion (A): [B(OH_2)_6]^{3+} and [B(OH)_4] | vedclass

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(D) The assertion is false because boron has a small atomic size and lacks $d$-orbitals in its valence shell, which prevents it from expanding its coo

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$A$ is false but $R$ is true

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(D) The assertion is false because boron has a small atomic size and lacks $d$-orbitals in its valence shell, which prevents it from expanding its coordination number beyond $4$. Therefore, the formation of an octahedral $[B(OH_2)_6]^{3+}$ complex is impossible.However, the reason is true because boron is electron-deficient ($sextet$ of electrons) and acts as a Lewis acid, reacting with Lewis bases like $OH^{-}$ to form the stable tetrahedral $[B(OH)_4]^{-}$ ion.Thus, $A$ is false but $R$ is true.

Column $I$	Column $II$
$A$. $Bi^{3+} \longrightarrow (BiO)^{+}$	$P$. Heat
$B$. $[AlO_2]^{-} \longrightarrow Al(OH)_3$	$Q$. Hydrolysis
$C$. $SiO_4^{4-} \longrightarrow Si_2O_7^{6-}$	$R$. Acidification
$D$. $(B_4O_7^{2-}) \longrightarrow [B(OH)_3]$	$S$. Dilution by water

Assertion $(A)$: $[B(OH_2)_6]^{3+}$ and $[B(OH)_4]^{-}$ form octahedral and tetrahedral structures.
Reason $(R)$: Being electron deficient, boron readily reacts with Lewis bases like $H_2O$ and $OH^{-}$.
The correct option among the following is

Similar Questions

Match the following:

Column $I$ Column $II$

$A$. $Bi^{3+} \longrightarrow (BiO)^{+}$ $P$. Heat

$B$. $[AlO_2]^{-} \longrightarrow Al(OH)_3$ $Q$. Hydrolysis

$C$. $SiO_4^{4-} \longrightarrow Si_2O_7^{6-}$ $R$. Acidification

$D$. $(B_4O_7^{2-}) \longrightarrow [B(OH)_3]$ $S$. Dilution by water

Draw the structure of boric acid showing hydrogen bonding. Which species is present in water? What is the hybridization of boron in this species?

When borax is dissolved in water,it gives an alkaline solution. The alkaline solution consists of the following products:

Hydrated $AlCl_3$ is used as :

What is the correct formula of Borazole?

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Assertion $(A)$: $[B(OH_2)_6]^{3+}$ and $[B(OH)_4]^{-}$ form octahedral and tetrahedral structures.Reason $(R)$: Being electron deficient, boron readily reacts with Lewis bases like $H_2O$ and $OH^{-}$.The correct option among the following is