Assertion: H_2O and XeF_4 both have a plane o | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) $H_2O$ has a bent structure ($sp^3$ hybridization) and possesses a plane of symmetry (the molecular plane). It is a polar molecule due to the net

Vedclass · Accepted Answer

Both Assertion and Reason are true,but Reason is $NOT$ the correct explanation of Assertion.

Vedclass · Answer

(A) $H_2O$ has a bent structure ($sp^3$ hybridization) and possesses a plane of symmetry (the molecular plane). It is a polar molecule due to the net dipole moment. $XeF_4$ has a square planar structure ($sp^3d^2$ hybridization) and possesses multiple planes of symmetry (including the molecular plane). It is non-polar because the individual bond dipoles cancel each other out. Both statements are true,but the polarity of the molecules is not the reason for the existence of a plane of symmetry. Therefore,the Reason is not the correct explanation of the Assertion.

Assertion: $H_2O$ and $XeF_4$ both have a plane of symmetry.
Reason: $H_2O$ is a polar molecule,whereas $XeF_4$ is a non-polar molecule.

Similar Questions

The correct order of $S-S$ bond length in the following oxyanions is:
$(I) \, S_2O_4^{2-}$
$(II) \, S_2O_5^{2-}$
$(III) \, S_2O_6^{2-}$

Which of the following is not a Lewis acid?

Pick out the isoelectronic structures from the following:
$\mathop {CH_3^+}\limits_{I}$ $\mathop {H_3O^{+}}\limits_{II}$ $\mathop {NH_3}\limits_{III}$ $\mathop {CH_3^-}\limits_{IV}$

Identify the incorrect statements among the following:
$(i) \ SF_6$ does not react with water
$(ii) \ SF_6$ is $sp^3d$ hybridized
$(iii) \ S_2O_3^{2-}$ is a linear ion
$(iv)$ There is no $\pi$-bonding in $SO_4^{2-}$ ion

The number of electrons in the valence shell of the central atom of a molecule is $8$. The molecule is

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Assertion: $H_2O$ and $XeF_4$ both have a plane of symmetry. Reason: $H_2O$ is a polar molecule,whereas $XeF_4$ is a non-polar molecule.