Assign A,B,C,D from given type of reaction. X | vedclass

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(A) The given reaction is: $3XeF_4 + 6H_2O \longrightarrow Xe + 2XeO_3 + 12HF + 1.5O_2$. In this reaction,the oxidation state of $Xe$ in $XeF_4$ is $+

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$A$. for disproportionation reaction.

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(A) The given reaction is: $3XeF_4 + 6H_2O \longrightarrow Xe + 2XeO_3 + 12HF + 1.5O_2$. In this reaction,the oxidation state of $Xe$ in $XeF_4$ is $+4$. In the products,$Xe$ is in $0$ oxidation state (in $Xe$) and $+6$ oxidation state (in $XeO_3$). Since the same element $(Xe)$ is simultaneously oxidized (from $+4$ to $+6$) and reduced (from $+4$ to $0$),this is a disproportionation reaction. Therefore,the correct assignment is $A$.

Assign $A$,$B$,$C$,$D$ from given type of reaction. $XeF_4 + H_2O \longrightarrow Xe + XeO_3 + HF + O_2$

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