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(C) In the given reaction: $5CO + I_2O_5 \longrightarrow 5CO_2 + I_2$.$1$. Oxidation state of $C$ in $CO$ is $+2$ and in $CO_2$ is $+4$. Since the oxi

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$C$. for either intermolecular redox reaction or displacement reaction.

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(C) In the given reaction: $5CO + I_2O_5 \longrightarrow 5CO_2 + I_2$.$1$. Oxidation state of $C$ in $CO$ is $+2$ and in $CO_2$ is $+4$. Since the oxidation state increases,$CO$ is oxidized.$2$. Oxidation state of $I$ in $I_2O_5$ is $+5$ and in $I_2$ is $0$. Since the oxidation state decreases,$I_2O_5$ is reduced.$3$. This is an intermolecular redox reaction where one substance is oxidized and another is reduced. It can also be classified as a displacement reaction where $CO$ displaces $I$ from $I_2O_5$.

Assign $A, B, C, D$ from the given type of reaction:
$5CO(g) + I_2O_5(s) \longrightarrow 5CO_2(g) + I_2(s)$

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Assign $A, B, C, D$ from the given type of reaction:$5CO(g) + I_2O_5(s) \longrightarrow 5CO_2(g) + I_2(s)$