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(B) In the given reaction: $NO (+2) + NO_2 (+4) \rightarrow N_2O_3 (+3)$.Here,the oxidation state of nitrogen changes from $+2$ and $+4$ to $+3$.Since

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for comproportionation reaction.

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(B) In the given reaction: $NO (+2) + NO_2 (+4) \rightarrow N_2O_3 (+3)$.Here,the oxidation state of nitrogen changes from $+2$ and $+4$ to $+3$.Since two different oxidation states of the same element combine to form a single product with an intermediate oxidation state,this is a comproportionation reaction.Comproportionation is a specific type of redox reaction where two reactants containing the same element in different oxidation states form a product in which the element is in an intermediate oxidation state.Therefore,the reaction is a comproportionation reaction.

Assign $A, B, C, D$ from the given type of reaction.
$NO + NO_2 \xrightarrow{-11 \ ^{\circ}C} N_2O_3$

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Assign $A, B, C, D$ from the given type of reaction.$NO + NO_2 \xrightarrow{-11 \ ^{\circ}C} N_2O_3$