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(C) In the reaction $Sn + PCl_5 \xrightarrow{\Delta} SnCl_4 + PCl_3$,the oxidation state of $Sn$ changes from $0$ to $+4$ (oxidation).The oxidation st

Vedclass · Accepted Answer

$C$. for either intermolecular redox reaction or displacement reaction.

Vedclass · Answer

(C) In the reaction $Sn + PCl_5 \xrightarrow{\Delta} SnCl_4 + PCl_3$,the oxidation state of $Sn$ changes from $0$ to $+4$ (oxidation).The oxidation state of $P$ changes from $+5$ to $+3$ (reduction).Since one reactant $(Sn)$ is oxidized and another reactant $(PCl_5)$ is reduced,this is an intermolecular redox reaction.Additionally,$Sn$ displaces $P$ from $PCl_5$,making it a displacement reaction.Therefore,the correct classification is $C$.

Assign $A, B, C, D$ from the given type of reaction.
$Sn + PCl_5 \xrightarrow{\Delta} SnCl_4 + PCl_3$

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Assign $A, B, C, D$ from the given type of reaction.$Sn + PCl_5 \xrightarrow{\Delta} SnCl_4 + PCl_3$