Assume each oil drop has a capacitance of $C$. If $n$ drops are combined to form a bigger drop,then the capacitance of the bigger drop $C^{\prime}$ would be

  • A
    $C^{\prime}=\frac{2 n^{1 / 3}}{3} C$
  • B
    $C^{\prime}=\frac{5 n^{1 / 3}}{4} C$
  • C
    $C^{\prime}=\frac{n^{1 / 3}}{5} C$
  • D
    $C^{\prime}=C \cdot n^{1 / 3}$

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