Assuming complete ionisation,arrange the foll | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Osmotic pressure is a colligative property that depends on the number of particles in the solution. The solution having a higher concentration of

Vedclass · Accepted Answer

$d < b < a < c$

Vedclass · Answer

(A) Osmotic pressure is a colligative property that depends on the number of particles in the solution. The solution having a higher concentration of particles will have a larger osmotic pressure.Osmotic pressure $(\pi)$ $\propto i 	imes C$,where $i$ is the van't Hoff factor and $C$ is the molarity.  Solution Concentration of particles $(i 	imes m)$   $(a) \ 0.5 \ m \ Li_2SO_4$ $3 	imes 0.5 = 1.5 \ m$   $(b) \ 0.5 \ m \ KCl$ $2 	imes 0.5 = 1.0 \ m$   $(c) \ 0.5 \ m \ Al_2(SO_4)_3$ $5 	imes 0.5 = 2.5 \ m$   $(d) \ 0.1 \ m \ BaCl_2$ $3 	imes 0.1 = 0.3 \ m$  Comparing the values: $0.3 Therefore,the correct order of increasing osmotic pressure is $d < b < a < c$.

Assuming complete ionisation,arrange the following solutions in order of increasing osmotic pressure.
$(a)$ $0.5 \ m \ Li_2SO_4$
$(b)$ $0.5 \ m \ KCl$
$(c)$ $0.5 \ m \ Al_2(SO_4)_3$
$(d)$ $0.1 \ m \ BaCl_2$

Similar Questions

Which solution is isotonic with $0.2 \ M \ H_2SO_4$?

Which of the following pairs of solutions is expected to be isotonic at the same temperature?

If a thin slice of sugar beet is placed in a concentrated solution of $NaCl$,then...

What would happen if a thin slice of sugar beet is placed in a concentrated solution of $NaCl$?

Explain reverse osmosis and the purification of water.

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Assuming complete ionisation,arrange the following solutions in order of increasing osmotic pressure.$(a)$ $0.5 \ m \ Li_2SO_4$$(b)$ $0.5 \ m \ KCl$$(c)$ $0.5 \ m \ Al_2(SO_4)_3$$(d)$ $0.1 \ m \ BaCl_2$