At 0, ^circ C and 1, atm pressure,a gas occup | vedclass

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(B) Using the combined gas law: $\frac{P_1 V_1}{T_1} = \frac{P_2 V_2}{T_2}$.Given:$P_1 = P$,$V_1 = 100\, cc$,$T_1 = 0 + 273 = 273\, K$.Conditions:$P_2

Vedclass · Accepted Answer

$88.9$

Vedclass · Answer

(B) Using the combined gas law: $\frac{P_1 V_1}{T_1} = \frac{P_2 V_2}{T_2}$.Given:$P_1 = P$,$V_1 = 100\, cc$,$T_1 = 0 + 273 = 273\, K$.Conditions:$P_2 = 1.5 P = \frac{3}{2} P$.$T_2 = T_1 + \frac{1}{3} T_1 = \frac{4}{3} T_1 = \frac{4}{3} 	imes 273\, K$.Calculation:$V_2 = V_1 	imes \frac{P_1}{P_2} 	imes \frac{T_2}{T_1} = 100 	imes \frac{P}{\frac{3}{2} P} 	imes \frac{\frac{4}{3} 	imes 273}{273}$.$V_2 = 100 	imes \frac{2}{3} 	imes \frac{4}{3} = 100 	imes \frac{8}{9} = \frac{800}{9} \approx 88.89\, cc$.

$P \ (bar)$	$\frac{PV}{RT}$
$1$	$1$
$2$	$1$
$3$	$1$
$4$	$1.5$
$5$	$2.0$

At $0\, ^\circ C$ and $1\, atm$ pressure,a gas occupies $100\, cc$. If the pressure is increased to $1.5$-times and temperature is increased by one-third of its absolute temperature,then the final volume of the gas will be .............. $cc$.

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