At $298 \ K$,the solubility product of $PbCl_2$ is $1.0 \times 10^{-6}$. What will be the solubility of $PbCl_2$ in moles/litre?

  • A
    $6.3 \times 10^{-3}$
  • B
    $1.0 \times 10^{-3}$
  • C
    $3.0 \times 10^{-3}$
  • D
    $4.6 \times 10^{-14}$

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