(D) Given: Ideal gas $A$ and $H_2$ gas are at the same pressure $(P)$ and volume $(V)$.From the ideal gas equation,$PV = nRT$,we have $n = \frac{PV}{R

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(D) Given: Ideal gas $A$ and $H_2$ gas are at the same pressure $(P)$ and volume $(V)$.From the ideal gas equation,$PV = nRT$,we have $n = \frac{PV}{RT}$.Since $P$ and $V$ are the same for both gases,$n_A T_A = n_{H_2} T_{H_2}$.Here,$n_A = \frac{3.0}{M_A}$ and $n_{H_2} = \frac{0.2}{2.0} = 0.1 \ mol$.Substituting the values: $\frac{3.0}{M_A} \times 300 = 0.1 \times 200$.$\frac{900}{M_A} = 20$.$M_A = \frac{900}{20} = 45 \ g \ mol^{-1}$.

Class 11 Chemistry States of Matter Ideal gas equation and Related gas laws

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At $300 \ K$,a sample of $3.0 \ g$ of gas $A$ occupies the same volume as $0.2 \ g$ of hydrogen $(H_2)$ at $200 \ K$ at the same pressure. The molar mass of gas $A$ is $...... \ g \ mol^{-1}$ (nearest integer). Assume that the gases behave as ideal gases.

JEE MAIN 2022 All JEE MAIN

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$55$
B
$105$
C
$60$
D
$45$

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At $300 \ K$,a sample of $3.0 \ g$ of gas $A$ occupies the same volume as $0.2 \ g$ of hydrogen $(H_2)$ at $200 \ K$ at the same pressure. The molar mass of gas $A$ is $...... \ g \ mol^{-1}$ (nearest integer). Assume that the gases behave as ideal gases.

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