At $500 \ K$,for a reversible reaction $A_{2(g)} + B_{2(g)} \rightleftharpoons 2 AB_{(g)}$ in a closed container,$K_C = 2 \times 10^{-5}$. In the presence of a catalyst,the equilibrium is attained $10$ times faster. The equilibrium constant $K_C$ in the presence of a catalyst at the same temperature is:

• A
  $2 \times 10^{-4}$
• B
  $2 \times 10^{-6}$
• C
  $2 \times 10^{-10}$
• D
  $2 \times 10^{-5}$