At $298 \ K$,the conductivity of $KCl$ solutions of molarity $0.1 \ M, 0.01 \ M$ and $1.0 \ M$ are recorded as $X, Y$ and $Z \ S \ cm^{-1}$ respectively. The correct relation between $X, Y$ and $Z$ is

Resistance of $0.2 \, M$ solution of an electrolyte is $50 \, \Omega$. The specific conductance of the solution is $1.4 \, S \, m^{-1}$. The resistance of $0.5 \, M$ solution of the same electrolyte is $280 \, \Omega$. The molar conductivity of $0.5 \, M$ solution of the electrolyte in $S \, m^2 \, mol^{-1}$ is:

The molar conductivity of $KCl$ solutions at different concentrations at $298 \, K$ are given below:

$c^{1/2} / (mol \, L^{-1})^{1/2}$	$\Lambda_m / S \, cm^2 \, mol^{-1}$
$0.000198$	$148.61$
$0.000309$	$148.29$
$0.000521$	$147.81$
$0.000989$	$147.09$

Show that a plot between $\Lambda_m$ and $c^{1/2}$ is a straight line. Determine the values of $\Lambda_m^o$ and $A$ for $KCl$.

If the resistivity of a $0.8 \ M \ KCl$ solution is $2.5 \times 10^{-3} \ \Omega \ cm$,calculate the molar conductivity of the solution.

In an aqueous solution,how does specific conductivity of electrolytes change with the addition of water?

Calculate the concentration of silver nitrate solution if molar conductivity and conductivity of silver nitrate at $25 \text{ }^\circ\text{C}$ are respectively $120 \text{ ohm}^{-1} \text{cm}^2 \text{mol}^{-1}$ and $0.0024 \text{ ohm}^{-1} \text{cm}^{-1}$. (in $\text{ M}$)