At T K,the RMS velocity of He is equal to th | vedclass

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(D) The formula for $RMS$ velocity is $v_{rms} = \sqrt{\frac{3RT}{M}}$.Given that the $RMS$ velocity of $He$ at $T \ K$ is equal to the $RMS$ velocity

Vedclass · Accepted Answer

$25$

Vedclass · Answer

(D) The formula for $RMS$ velocity is $v_{rms} = \sqrt{\frac{3RT}{M}}$.Given that the $RMS$ velocity of $He$ at $T \ K$ is equal to the $RMS$ velocity of $SO_2$ at $127^{\circ} C$ $(400 \ K)$:$\sqrt{\frac{3RT}{M_{He}}} = \sqrt{\frac{3R(400)}{M_{SO_2}}}$$\frac{T}{M_{He}} = \frac{400}{M_{SO_2}}$Given $M_{He} = 4 \ g/mol$ and $M_{SO_2} = 64 \ g/mol$:$\frac{T}{4} = \frac{400}{64}$$T = \frac{400 	imes 4}{64} = \frac{1600}{64} = 25 \ K$.

At $T \ K$,the $RMS$ velocity of $He$ is equal to the $RMS$ velocity of $SO_2$ at $127^{\circ} C$. What is $T$ (in $K$)?

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