At a certain place,the angle of dip is $30^{\circ}$ and the horizontal component of the Earth's magnetic field is $0.5 \ G$. The Earth's total magnetic field (in $G$) at that place is:

  • A
    $\frac{1}{\sqrt{3}}$
  • B
    $\frac{1}{2}$
  • C
    $\sqrt{3}$
  • D
    $1$

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Similar Questions

Assume the dipole model for Earth's magnetic field $B$,which is given by:
$B_{V} = \text{vertical component of magnetic field} = \frac{\mu_{0}}{4\pi} \frac{2m \cos \theta}{r^{3}}$
$B_{H} = \text{horizontal component of magnetic field} = \frac{\mu_{0}}{4\pi} \frac{m \sin \theta}{r^{3}}$
where $\theta = 90^{\circ} - \text{latitude}$ as measured from the magnetic equator.
$(a)$ Find the loci of points for which $|\vec{B}|$ is minimum.

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At which place does the Earth's magnetism become horizontal?

If the dip circle is set at $45^{\circ}$ to the magnetic meridian,then the apparent dip is $30^{\circ}$. The true dip of the place is:

Explain magnetic declination.

At a place,the horizontal and vertical intensities of the Earth's magnetic field are $0.30 \ G$ and $0.173 \ G$ respectively. The angle of dip at this place is.....$^o$

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