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(B) The Vander Waal's equation for $1$ mole of gas is $(p + \frac{a}{V_m^2})(V_m - b) = RT$. At high temperature and low pressure,the volume of the ga

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$p V_m = RT$

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(B) The Vander Waal's equation for $1$ mole of gas is $(p + \frac{a}{V_m^2})(V_m - b) = RT$. At high temperature and low pressure,the volume of the gas $V_m$ is very large,so $V_m \gg b$,which means $(V_m - b) \approx V_m$. Also,at low pressure,the term $\frac{a}{V_m^2}$ becomes negligible compared to $p$. Substituting these approximations into the equation,we get $p V_m = RT$,which is the ideal gas equation.

At high temperature and low pressure,the Vander Waal's equation is reduced to

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