(A) The time period of a vibration magnetometer is given by the formula: $T = 2\pi \sqrt{\frac{I}{MH}}$.Here,$I$ is the moment of inertia and $M$ is t

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(A) The time period of a vibration magnetometer is given by the formula: $T = 2\pi \sqrt{\frac{I}{MH}}$.Here,$I$ is the moment of inertia and $M$ is the magnetic moment of the magnet,both of which remain constant.Thus,$T \propto \frac{1}{\sqrt{H}}$,which implies $H \propto \frac{1}{T^2}$.Given $T_A = 2 \ s$ and $T_B = 3 \ s$,we have the ratio:$\frac{H_A}{H_B} = \frac{T_B^2}{T_A^2} = \left(\frac{3}{2}\right)^2 = \frac{9}{4}$.Therefore,the ratio $H_A : H_B$ is $9:4$.

Class 12 Physics Magnetism and Matter Magnetic Equipment's (Tangent galvanometer, Vibration magnetometer and Neutral point)

Medium

At two places $A$ and $B$,using a vibration magnetometer,a magnet vibrates in a horizontal plane. Its respective periodic times are $2 \ s$ and $3 \ s$. At these places,the Earth's horizontal components are $H_A$ and $H_B$ respectively. Then the ratio between $H_A$ and $H_B$ will be:

A
$9:4$
B
$3:2$
C
$4:9$
D
$2:3$

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Magnetism and Matter

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Magnetic Equipment's (Tangent galvanometer, Vibration magnetometer and Neutral point)

$A$ tangent galvanometer shows a deflection of $45^{\circ}$ when a $10 \, mA$ current passes through it. If the horizontal component of the Earth's magnetic field is $3.6 \times 10^{-5} \, T$ and the radius of the coil is $10 \, cm$,find the number of turns in the coil.

Medium

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The time period of a vibration magnetometer is $T_0$. Its magnet is replaced by another magnet whose moment of inertia is $3$ times and magnetic moment is $1/3$ of the initial magnet. The time period now will be

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$A$ bar magnet $A$ of magnetic moment $M_A$ is found to oscillate at a frequency twice that of magnet $B$ of magnetic moment $M_B$ when placed in a vibrating magnetometer. We may say that

Medium

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The periodic time of a magnet in a vibration magnetometer is $T_0$. If the magnet is replaced by another magnet whose moment of inertia is three times and magnetic moment is one-third of the original magnet, then the time period of the new magnet will be:

DifficultMHT CET 2026

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At a certain place, a magnet makes $30$ oscillations per minute. At another place where the magnetic field is doubled, its time period will be

MediumTS EAMCET 2015

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At two places $A$ and $B$,using a vibration magnetometer,a magnet vibrates in a horizontal plane. Its respective periodic times are $2 \ s$ and $3 \ s$. At these places,the Earth's horizontal components are $H_A$ and $H_B$ respectively. Then the ratio between $H_A$ and $H_B$ will be:

Similar Questions

$A$ tangent galvanometer shows a deflection of $45^{\circ}$ when a $10 \, mA$ current passes through it. If the horizontal component of the Earth's magnetic field is $3.6 \times 10^{-5} \, T$ and the radius of the coil is $10 \, cm$,find the number of turns in the coil.

The time period of a vibration magnetometer is $T_0$. Its magnet is replaced by another magnet whose moment of inertia is $3$ times and magnetic moment is $1/3$ of the initial magnet. The time period now will be

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