At which temperature does a 0.006% w/V urea | vedclass

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(B) The osmotic pressure formula is $\pi = CRT$,where $C$ is the molar concentration.Given: $\pi = 0.0246 \ atm$,$R = 0.0821 \ L \ atm \ K^{-1} \ mol^

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$300$

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(B) The osmotic pressure formula is $\pi = CRT$,where $C$ is the molar concentration.Given: $\pi = 0.0246 \ atm$,$R = 0.0821 \ L \ atm \ K^{-1} \ mol^{-1}$.$0.006\% \ w/V$ means $0.006 \ g$ of urea in $100 \ mL$ of solution,which is $0.06 \ g/L$.Molar mass of urea $(NH_2CONH_2) = 60 \ g/mol$.$C = \frac{	ext{mass}}{	ext{molar mass} 	imes 	ext{volume in L}} = \frac{0.06 \ g}{60 \ g/mol 	imes 1 \ L} = 0.001 \ M$.Using $\pi = CRT$:$0.0246 = 0.001 	imes 0.0821 	imes T$.$T = \frac{0.0246}{0.0000821} \approx 300 \ K$.

At which temperature does a $0.006\% \ w/V$ urea solution have an osmotic pressure of $0.0246 \ atm$ (in $K$)?

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