The atomic number of a nucleus after a beta-e | vedclass

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Question

(C) During $\beta$-emission,a neutron in the nucleus is converted into a proton and an electron ($\beta$-particle). The emitted electron is ejected fr

Vedclass · Accepted Answer

$41$

Vedclass · Answer

(C) During $\beta$-emission,a neutron in the nucleus is converted into a proton and an electron ($\beta$-particle). The emitted electron is ejected from the nucleus,while the proton remains. This increases the atomic number $(Z)$ by $1$ while the mass number $(A)$ remains unchanged. The reaction is represented as: $_{40}X 	o _{41}Y + _{-1}e^0$. Therefore,the new atomic number is $40 + 1 = 41$.

The atomic number of a nucleus after a $\beta$-emission from a nucleus with an atomic number of $40$ will be:

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