Bag $I$ contains $3$ red and $4$ black balls. Bag $II$ contains $5$ red and $6$ black balls. If one ball is drawn at random from one of the bags, and it is found to be red, then the probability that it was drawn from Bag $II$, is

  • A
    $\frac{33}{68}$
  • B
    $\frac{35}{68}$
  • C
    $\frac{37}{68}$
  • D
    $\frac{41}{68}$

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