The base strength order of H_3C-CH_2^- (i),H_ | vedclass

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(A) The base strength of a conjugate base is inversely proportional to the acidity of its corresponding acid.The acidity order of the corresponding hy

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$(i) > (ii) > (iii)$

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(A) The base strength of a conjugate base is inversely proportional to the acidity of its corresponding acid.The acidity order of the corresponding hydrocarbons is: $HC \equiv CH > H_2C=CH_2 > H_3C-CH_3$.This is because the $s$-character in the hybrid orbitals increases from $sp^3$ $(25\%)$ to $sp^2$ $(33.3\%)$ to $sp$ $(50\%)$,making the carbon more electronegative and the conjugate base more stable.Since the stability of the conjugate base increases in the order $H_3C-CH_2^-  H_2C=CH^- > HC \equiv C^-$.Therefore,the correct order is $(i) > (ii) > (iii)$.

List-$I$	List-$II$
$A$. Ethane	$1$. $2 \ sp$ carbons
$B$. Ethylene	$2$. $6 \ sp^2$ carbons
$C$. Acetylene	$3$. $2 \ sp^3$ carbons
$D$. Benzene	$4$. $2 \ sp^2$ carbons
	$5$. $1 \ sp$ and $1 \ sp^2$ carbons

The base strength order of $H_3C-CH_2^-$ $(i)$,$H_2C=CH^-$ $(ii)$,and $HC \equiv C^-$ $(iii)$ is:

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