Based on VSEPR theory,the number of 90^{circ} | vedclass

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Question

(B) The molecule $BrF_5$ has a square pyramidal geometry with one lone pair on the central $Br$ atom.Due to the strong repulsion between the lone pair

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(B) The molecule $BrF_5$ has a square pyramidal geometry with one lone pair on the central $Br$ atom.Due to the strong repulsion between the lone pair and the bonding pairs,the equatorial $F$ atoms are pushed downwards.Consequently,the bond angles between the axial $F$ and the equatorial $F$ atoms are reduced from $90^{\circ}$ to approximately $84.8^{\circ}$.Therefore,there are no $90^{\circ}$ $F-Br-F$ bond angles in the molecule.

List-$I$	List-$II$
$I$. $XeF_4$	$A$. See-saw
$II$. $I_3^-$	$B$. Tetrahedral
$III$. $XeO_2F_2$	$C$. Bond angle $90^o$
$IV$. $SO_4^{2-}$	$D$. Linear

Based on $VSEPR$ theory,the number of $90^{\circ}$ $F-Br-F$ bond angles in $BrF_5$ is

Similar Questions

What is the type of molecule for $SF_4$ among $AB_4$,$AB_4E$,and $AB_3E_2$?

Match List-$I$ with List-$II$ and select the correct answer using the codes given below the lists.

List-$I$ List-$II$

$I$. $XeF_4$ $A$. See-saw

$II$. $I_3^-$ $B$. Tetrahedral

$III$. $XeO_2F_2$ $C$. Bond angle $90^o$

$IV$. $SO_4^{2-}$ $D$. Linear

Which of the following molecules has the smallest bond angle?

In which of the following,are the molecules arranged in the increasing order of their bond angles?

Which of the following structures is the most preferred and has the lowest energy for $SO_3$?

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