Benzoic acid on treatment with hydrazoic acid in the presence of concentrated sulphuric acid gives:

Rearrange the following in the increasing order of acidic strength:
$(i)$ benzoic acid $(ii)$ $p$-methoxybenzoic acid $(iii)$ $o$-methoxybenzoic acid

Formic acid and acetic acid can be distinguished by

$C_4H_7OCl$ $(x)$ $\xrightarrow{NH_3} C_4H_9NO$ $\xrightarrow{Br_2 + KOH} CH_3-CH_2-CH_2-NH_2$. Compound $x$ is:

Arrange the products $I$,$II$,$III$ from the following reactions in decreasing order of their acid strength.
$A) \text{Propylbenzene} \xrightarrow[\text{ (ii) } H_3O^{+}]{\text{ (i) } KMnO_4 / OH^{-}} I$
$B) CH_3COOH \xrightarrow[\text{ (ii) } H_2O]{\text{ (i) } Br_2 / \text{red } P} II$
$C) \text{Bromobenzene}$ $\xrightarrow[\substack{\text{ (ii) } CO_2 / \text{dry ether} \\ \text{ (iii) } H_3O^{+}}]{\text{ (i) } Mg / \text{dry ether}} III$

The correct order of increasing acidic strength among the following is: