Bond angle is minimum for

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(D) The correct option is $(D)$. As we move down the group $16$,the electronegativity of the central atom decreases. Consequently,the bond pairs are f

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$H_2Te$

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(D) The correct option is $(D)$. As we move down the group $16$,the electronegativity of the central atom decreases. Consequently,the bond pairs are further away from the central atom,leading to reduced repulsion between them,which results in a decrease in the bond angle.All these molecules are hydrides of group $16$ elements. Although the central atoms undergo $sp^3$ hybridization (theoretically expecting a bond angle of $109.5^{\circ}$),the actual bond angles are significantly smaller due to the repulsion between lone pairs and bond pairs. As the size of the central atom increases from $O$ to $Te$,the bond length increases and the repulsion between the bond pairs decreases,leading to a minimum bond angle in $H_2Te$.						$H_2O$			$104.5^{\circ}$							$H_2S$			$92.1^{\circ}$							$H_2Se$			$91^{\circ}$							$H_2Te$			$90^{\circ}$

$A$. Trigonal planar	$I$. $PCl_5$
$B$. Tetrahedral	$II$. $SF_6$
$C$. Trigonal bipyramidal	$III$. $BF_3$
$D$. Octahedral	$IV$. $CCl_4$

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Match the molecular geometries in List-$I$ with their corresponding molecules in List-$II$:
$A$. Trigonal planar $I$. $PCl_5$
$B$. Tetrahedral $II$. $SF_6$
$C$. Trigonal bipyramidal $III$. $BF_3$
$D$. Octahedral $IV$. $CCl_4$

The correct match for $A, B, C, D$ is:

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