By heating a mixture of $CHCl_3$ with silver powder,the compound formed is

The products of the following reaction $CH_3-C \equiv C-CH_2-CH_3 \xrightarrow[(2)\ H_2O]{(1)\ O_3}$ are:

$1$-Alkyne and $2$-alkyne can be distinguished by

The compound $X \ (C_5H_8)$ reacts with ammoniacal $AgNO_3$ to give a white precipitate and reacts with excess of $KMnO_4$ to give the acid,$(CH_3)_2CHCOOH$. Therefore,$X$ is:

Calcium carbide $+ D_2 O \longrightarrow \underline{X} + Ca(OD)_2$.
The hybridisation of carbon atom$(s)$ in $X$ is:

What is obtained when calcium carbide reacts with heavy water?