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(B) According to the photoelectric effect, the number of photoelectrons emitted per second is directly proportional to the intensity of the incident l

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number of emitted electrons increases

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(B) According to the photoelectric effect, the number of photoelectrons emitted per second is directly proportional to the intensity of the incident light, provided the frequency is above the threshold frequency $(v > v_0)$.Increasing the intensity means increasing the number of photons incident per unit area per unit time. Since each photon interacts with one electron, the number of emitted photoelectrons increases.The maximum kinetic energy of the photoelectrons depends only on the frequency of the incident light $(K_{max} = hv - \Phi_0)$. Since the frequency is kept constant, the kinetic energy of each emitted photoelectron remains unchanged.Therefore, increasing the intensity only increases the number of emitted electrons.

By increasing the intensity of incident light, keeping the frequency $(v > v_0)$ fixed on the surface of a metal:

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