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(B) The magnetic field $B$ inside a toroidal solenoid is given by the formula $B = \mu_0 n I$,where $n$ is the number of turns per unit length $(n = N

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will become three times

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(B) The magnetic field $B$ inside a toroidal solenoid is given by the formula $B = \mu_0 n I$,where $n$ is the number of turns per unit length $(n = N / 2\pi r)$.Substituting $n$,we get $B = \mu_0 (N / 2\pi r) I$.Here,$N$ is the total number of turns,$I$ is the current,and $r$ is the radius of the toroid.Since $B \propto N$,if the number of turns $N$ is increased by $3$ times,the magnetic field $B$ will also increase by $3$ times.

By increasing the number of turns $3$ times in a toroidal solenoid,the magnetic field:

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