By passing electric current,NaClO_{3} is conv | vedclass

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(C) The balanced chemical equation is: $NaClO_{3} + H_{2}O \rightarrow NaClO_{4} + H_{2}$.The oxidation state of $Cl$ in $NaClO_{3}$ is $+5$ and in $N

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$1.5$

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(C) The balanced chemical equation is: $NaClO_{3} + H_{2}O ightarrow NaClO_{4} + H_{2}$.The oxidation state of $Cl$ in $NaClO_{3}$ is $+5$ and in $NaClO_{4}$ is $+7$.The change in oxidation state is $7 - 5 = 2$,which means $2$ moles of electrons are involved per mole of $NaClO_{3}$.Thus,$2 \ F$ of charge is required to produce $1$ mole of $NaClO_{4}$.Therefore,$1 \ F$ of charge produces $1/2$ mole of $NaClO_{4}$.For $3 \ F$ of charge,the moles of $NaClO_{4}$ formed $= (1/2) 	imes 3 = 1.5 \ mol$.

By passing electric current,$NaClO_{3}$ is converted into $NaClO_{4}$ according to the following equation:
$NaClO_{3} + H_{2}O \rightarrow NaClO_{4} + H_{2}$
How many moles of $NaClO_{4}$ will be formed when $3 \ F$ of charge is passed through $NaClO_{3}$?

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By passing electric current,$NaClO_{3}$ is converted into $NaClO_{4}$ according to the following equation:$NaClO_{3} + H_{2}O \rightarrow NaClO_{4} + H_{2}$How many moles of $NaClO_{4}$ will be formed when $3 \ F$ of charge is passed through $NaClO_{3}$?