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(C) The atmospheric pressure is $P_{atm} = 760\, mm$ of $Hg$.The pressure in the lungs is $P_{lungs} = 750\, mm$ of $Hg$.The pressure difference creat

Vedclass · Accepted Answer

$13.6$

Vedclass · Answer

(C) The atmospheric pressure is $P_{atm} = 760\, mm$ of $Hg$.The pressure in the lungs is $P_{lungs} = 750\, mm$ of $Hg$.The pressure difference created is $\Delta P = P_{atm} - P_{lungs} = 760\, mm - 750\, mm = 10\, mm$ of $Hg$.This pressure difference supports a column of water of height $h$ in the straw.Using the hydrostatic pressure formula $\Delta P = h_w ho_w g = h_{Hg} ho_{Hg} g$,we have:$h_w ho_w = h_{Hg} ho_{Hg}$Given $h_{Hg} = 10\, mm = 1\, cm$,$ho_{Hg} = 13.6\, g/cm^3$,and $ho_w = 1\, g/cm^3$:$h_w 	imes 1\, g/cm^3 = 1\, cm 	imes 13.6\, g/cm^3$$h_w = 13.6\, cm$.

By sucking through a straw,a student can reduce the pressure in his lungs to $750\, mm$ of $Hg$ (density $= 13.6\, g/cm^3$). Using the straw,he can drink water from a glass up to a maximum depth of ....... $cm$.

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