Calcium imide on hydrolysis will give gas (B) | vedclass

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(A) Calcium imide $(CaNH)$ on hydrolysis gives gas $NH_3$ and $Ca(OH)_2$. So $(B)$ is $NH_3$.$CaNH + 2H_2O \rightarrow NH_3 + Ca(OH)_2$$NH_3$ on oxida

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$NH_3, N_2, Mg_3N_2$

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(A) Calcium imide $(CaNH)$ on hydrolysis gives gas $NH_3$ and $Ca(OH)_2$. So $(B)$ is $NH_3$.$CaNH + 2H_2O \rightarrow NH_3 + Ca(OH)_2$$NH_3$ on oxidation by bleaching powder $(CaOCl_2)$ gives gas $N_2$. So $(C)$ is $N_2$.$3CaOCl_2 + 2NH_3 \rightarrow 3CaCl_2 + 3H_2O + N_2$$N_2$ on reaction with magnesium gives compound $Mg_3N_2$. So $(D)$ is $Mg_3N_2$.$N_2 + 3Mg \rightarrow Mg_3N_2$$Mg_3N_2$ on hydrolysis gives $NH_3$,which is $(B)$.$Mg_3N_2 + 6H_2O \rightarrow 3Mg(OH)_2 + 2NH_3$Therefore,$(B), (C)$ and $(D)$ are $NH_3, N_2, Mg_3N_2$.

Calcium imide on hydrolysis will give gas $(B)$ which on oxidation by bleaching powder gives gas $(C)$. Gas $(C)$ on reaction with magnesium gives compound $(D)$. $(D)$ on hydrolysis gives again gas $(B)$. $(B)$,$(C)$ and $(D)$ are

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